Operation of Matrices
Digital Handwritten Lesson
New Millennium Academy
Birauta, Pokhara-17, Kaski, Nepal | nripendraswaracharya.com.np
Class 9 – Matrix Operations & Properties
Optional Mathematics | Unit: Matrices | Class Notes
Course Overview
INTRO Learning Objectives
In this session, we will explore the fundamental operations performed on matrices and observe the algebraic properties that govern matrix addition and subtraction using numerical examples.
1 Operations of Matrices
a) Multiplication by Scalar
When a matrix is multiplied by a scalar (a real number), every individual element inside the matrix is multiplied by that number.
Let scalar be $3$ and Matrix $A = \begin{pmatrix} 2 & -1 \\ 4 & 5 \end{pmatrix}$. Then:
$$3 \cdot A = 3 \begin{pmatrix} 2 & -1 \\ 4 & 5 \end{pmatrix} = \begin{pmatrix} 3 \times 2 & 3 \times (-1) \\ 3 \times 4 & 3 \times 5 \end{pmatrix} = \begin{pmatrix} 6 & -3 \\ 12 & 15 \end{pmatrix}$$b) Addition and Subtraction of Matrices
Two matrices can be added or subtracted if and only if they have the same order. The operation is performed by adding or subtracting the corresponding elements.
If $A = \begin{pmatrix} 5 & 2 \\ 1 & 6 \end{pmatrix}$ and $B = \begin{pmatrix} 3 & 4 \\ 0 & 2 \end{pmatrix}$:
$$A + B = \begin{pmatrix} 5 + 3 & 2 + 4 \\ 1 + 0 & 6 + 2 \end{pmatrix} = \begin{pmatrix} 8 & 6 \\ 1 & 8 \end{pmatrix}$$ $$A - B = \begin{pmatrix} 5 - 3 & 2 - 4 \\ 1 - 0 & 6 - 2 \end{pmatrix} = \begin{pmatrix} 2 & -2 \\ 1 & 4 \end{pmatrix}$$2 Properties of Matrices (Numerical Proofs)
Let us define three $2 \times 2$ matrices to observe the following properties:
$$A = \begin{pmatrix} 2 & 5 \\ 1 & 4 \end{pmatrix}, \quad B = \begin{pmatrix} 3 & -1 \\ 0 & 2 \end{pmatrix}, \quad C = \begin{pmatrix} -2 & 4 \\ 5 & 1 \end{pmatrix}$$1. Closure Property (Addition and Subtraction)
Proof for Addition:
Proof for Subtraction:
2. Commutative Property (Addition)
Proof:
First, calculate $\text{L.H.S.} (A + B)$:
Next, calculate $\text{R.H.S.} (B + A)$:
3. Associative Property (Addition)
Proof:
Calculate $\text{L.H.S. } ((A + B) + C)$:
We already know $A + B = \begin{pmatrix} 5 & 4 \\ 1 & 6 \end{pmatrix}$. Now add $C$:
Calculate $\text{R.H.S. } (A + (B + C))$:
First find $(B + C)$:
Now add $A$ to $(B + C)$:
4. Additive Inverse
Proof:
Given $A = \begin{pmatrix} 2 & 5 \\ 1 & 4 \end{pmatrix}$, its negative matrix is $-A = \begin{pmatrix} -2 & -5 \\ -1 & -4 \end{pmatrix}$.
5. Additive Identity
Proof:
Let $\mathbf{O} = \begin{pmatrix} 0 & 0 \\ 0 & 0 \end{pmatrix}$ and $A = \begin{pmatrix} 2 & 5 \\ 1 & 4 \end{pmatrix}$.
Course material curated by Mr. Nripendraswar Acharya